bank Exam Numerical Ability Percentage

in a examination in which full marks were 1000,a got 20%more than b,b 10%more than c and c 20%less than d.if a got 660 marks,what percentage of full marks were obtained by d?

Read Solution (Total 1)

625

Let the marks obtained by d is x, then
Marks of c= 0.8x
Marks of b= 1.1*c =1.1*0.8x= 0.88x
Marks of a= 1.2*b =1.2*0.88x= 660
=> x = 660/(1.2*0.88) = 625
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