wap to find desired character in the string and find ascii value in java

• import java.io.IOException;
  import java.util.*;
  public class ibmchstr {
  public static void main(String args[]) throws IOException{
  Scanner sc=new Scanner(System.in);
  int x=0;
  System.out.println("enter the string");
  String s=sc.nextLine();
  System.out.println("enter the char to search");
  char ch=(char)System.in.read();
  for(int i=0;i
• 7 years agoHelpfull: Yes(2) No(2)
• import java.io.*;
  import java.lang.*;
  public class CharToASCII{
  public static void main(String args[]) throws IOException{
  BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
  System.out.println("Enter the char:");
  String str = buff.readLine();
  for ( int i = 0; i < str.length(); ++i ){
  char c = str.charAt(i);
  int j = (int) c;// your work is done here
  System.out.println("ASCII OF "+c +" = " + j + ".");
  }
  }
  }
• 7 years agoHelpfull: Yes(2) No(0)
• import java.io.*;
  import java.lang.*;
  public class CharToASCII{
  public static void main(String args[]) throws IOException{
  BufferedReader buff = new BufferedReader(new InputStreamReader(System.in));
  System.out.println("Enter the char:");
  String str = buff.readLine();
  for ( int i = 0; i < str.length(); ++i ){
  char c = str.charAt(i);
  int j = (int) c;// your work is done here
  System.out.println("ASCII OF "+c +" = " + j + ".");
  }
  }
  }
• 6 years agoHelpfull: Yes(1) No(0)
• @Vicky after that
• 7 years agoHelpfull: Yes(0) No(0)
• @ashish nayak i had posted full solution but i dono why its look lk this
• 7 years agoHelpfull: Yes(0) No(0)
• OK can you please mail me ashish.al19@gmail.com
• 7 years agoHelpfull: Yes(0) No(0)
• @vicky please send me that code ashish.al19@gmail.com
• 7 years agoHelpfull: Yes(0) No(0)
• public JavaApplication() {
  }
  
  public static void main(String[] args) {
  Scanner sc = new Scanner(System.in);
  
  System.out.println("Enter the String");
  String s = sc.nextLine();
  int count = (s.length()) + 1;
  
  System.out.println("Enter the character");
  char c = sc.next().charAt(0);
  //Character c=new Character('a');
  for (int i = 0; i < s.length(); i++) {
  if (c == s.charAt(i)) {
  System.out.println("yes it is present");
  int j = (int) c;
  System.out.println("Your ASCII Value " + j);
  count--;
  }
  if (count == 0) {
  System.out.println("it is not present");
  }
  }
  }
  }
• 6 years agoHelpfull: Yes(0) No(0)
• don't they prefer c language?
• 5 years agoHelpfull: Yes(0) No(0)
• import java.util.*;
  import java.io.*;
  import java.lang.*;
  
  public class DesiredChar
  {
  public static void main (String[] args)
  {
  int position=0;
  System.out.println("Enter The String: ");
  Scanner sc=new Scanner(System.in);
  String str=sc.nextLine();
  System.out.println("Enter The Character to find: ");
  char ch=sc.next().charAt(0);
  position=str.indexOf(ch);
  if(position>=0)
  {
  System.out.println("The position of "+ch+" is "+(position));
  System.out.println("THe Ascii value of "+ch+" is "+(int)ch);
  }
  else
  System.out.println(ch+" is not Present in the Given string");
  }
  }
• 5 years agoHelpfull: Yes(0) No(0)
• import java.util.Scanner;
  public class Main
  {
  public static void main(String[] args)
  {
  Scanner sc= new Scanner (System.in);
  String str=sc.nextLine();
  char ch= sc.next(".").charAt(0);
  System.out.println(ascii(str,ch));
  }
  static int ascii (String str,char ch)
  {
  for (int i=0;i
• 4 years agoHelpfull: Yes(0) No(0)
• import java.util.Scanner;
  public class Main
  {
  
  public static void main(String []args){
  Scanner sc=new Scanner(System.in);
  String name=sc.nextLine(); //input of a string
  char n = sc.next().charAt(0); //input of the string you need to find
  int val=name.indexOf(n);
  if(val != -1){
  System.out.println("present");
  System.out.println((int)n);
  }else{
  System.out.println("no");
  }
  }
  }
• 4 years agoHelpfull: Yes(0) No(0)