IBM
Company
Numerical Ability
Sequence and Series
5/7,18/11,09/11,15/08,13/15,12/15,17/19,09/02,?
Read Solution (Total 15)
-
- two series present
one is 5/7,9/11, 13/15, 17/19, x/(x+2)
it looks like 5,7,9,11,13,15,17,19,so numerator is 21 and then denominator is 23
ans is 21/23 - 7 years agoHelpfull: Yes(38) No(1)
- Odd sequence gets incremented by 4 and even sequence decrements by 3
I.e
5+4/7+4=9/11
18/11%18-3/11-3=15/8
Soon....
Ans is 21/23 ie 17+4/19+4 - 7 years agoHelpfull: Yes(10) No(0)
- numerator +4
denomianator +4 and so on in every odd place of the series
ans:21/23 - 7 years agoHelpfull: Yes(2) No(1)
- Answer:21/23
- 7 years agoHelpfull: Yes(2) No(1)
- Ans:21/23
- 7 years agoHelpfull: Yes(2) No(1)
- 5----9-----13---------17---------21
7-----11------15--------19-------23
21/23
see alternate series - 7 years agoHelpfull: Yes(1) No(0)
- 5/7,18/11,09/11,15/08,13/15,12/5,17/19,09/02
alternate series
5+2/7+2
18-3/11-3
ans-06/-1 - 7 years agoHelpfull: Yes(0) No(14)
- in each series, the difference between the two number in numerator and denominators are same order,
hence after compairing difference b/t two no,s, the next series is = 21/23 - 7 years agoHelpfull: Yes(0) No(0)
- Ans. 21/23
The odd positions forms a series, 5/7, 9/11, 13/15, 17/19, ...
In every consecutive term, the numerator and the denominator is larger by 4 from the numerator and the denominator of the previous number.
Following this the next number would be (17+4)/(19+4) = 21/23 - 7 years agoHelpfull: Yes(0) No(0)
- odd sequence is in the sequence of odd numbers 5,7,.... so the last one will be 21/23 since 21 is the next odd number to 19
- 7 years agoHelpfull: Yes(0) No(0)
- 5/7,18/11,09/11,15/08,13/15,12/15,17/19,09/02
the numbers at 1,3,5...(odd position) are x+4/(y+4)
the numbers at 2,4,6,....(even position) are z-3 / (pattern of one 7 then 11 is repeated after one digit the other one is repeated).
so the next numbers are 21/23, 6/2 - 7 years agoHelpfull: Yes(0) No(0)
- for the alternative numbers, both the numerator and denominator is add with 4
let us take 1st term and 3rd term,
numerator:5+4=9
denominator:7+4=11
same logic should be apply for all the alternative numbers
ans:21/23 - 7 years agoHelpfull: Yes(0) No(0)
- Alternate series : 5/7 ,09/11, 13/15 ,17/19 , 21/23
Adding 4 for both numerator and denominator - 7 years agoHelpfull: Yes(0) No(0)
- answer=21/2
5/7,18/11,9/11,15/8,13/15,12/15,17/19,9/2,?
skip 18/11,9/11,skip,13/15,17/15,skip,9/2,6/2(so denominator is 2)
and numerator is based on this (5/7,9/11,13/15,17/19,?) 5+4=9,9+4=13,13+4=17,17+4=21 - 6 years agoHelpfull: Yes(0) No(0)
- Ans::21/23.
x/x+2=21/21+2=21/23 - 6 years agoHelpfull: Yes(0) No(0)
IBM Other Question