Each of A,B and C has some coins with them.A gave two coins to B,who then gave 4 coins to C,who,in turn, gave six coins to A.Now,if each of them has the same number of coins,and the number of coins in the beginning were in the ratio x:y:z,what is the minimum possible value of x+y+z?

1) 3
2) 5
3) 4
4) 15

• 5
  ratio will be 1:2:2
  when initial coins are 4:8:8
• 12 years agoHelpfull: Yes(0) No(0)