MBA Exam

The sum of the first 13 terms of an arithmetic progression is 26k and the sum of the next 12 terms of the progression is 49k, where k is a constant. What is the ratio of the thirteenth term to the seventh term of the progression?

1) 1 : 1
2) 3 : 2
3) 2 : 3
4) 3 : 4
5) 2 : 1

Read Solution (Total 1)

3:2

(13/2)*(2a+12d)= 26k
a+6d= 2k which is seventh term.

also (25/2)*(2a+24d)=75k
a+12d= 3k which is 13th term

ratio of the thirteenth term to the seventh term of the progression = 3k:2k or
3:2
11 years agoHelpfull: Yes(0) No(0)

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