The sum of the series upto n terms will be:5*8 + 8*11+ 11*14......upto n termsPlz post a sol to this Q

1) (n+1)[3(n+1)^2 +6(n+1)+1]-10
2) (n+1)[3(n+1)^2 +6(n+1)+1]+10
3) (n+1)[3(n+1)+6(n+1)^2+1]-10
4) (n+1)[3(n+1)+6(n+1)^2+1]+10