Two men are going along a track rail in the opposite direction. One goods train crossed the first person in 20 sec. After 10 min the train crossed the other person who is coming in opposite direction in 18 sec .After the train has passed, when the two persons will meet?

• 72 minutes
• 13 years agoHelpfull: Yes(4) No(4)
• This can be solved if we assume that both the persons are walking with the same
  speed
  
  Let the length of train be L,
  the speed of the train be x m/s,
  the speed of the men be y m/s
  and the distance between the two men initially be D
  
  
  The train took 20 seconds to cross a man going inthe same direction
  
  So relative speed is x-y = L/20 m/s --- I
  
  It took 18 seconds to cross the man coming in the opposite direction.
  
  Again relative speed is x+y = L/18 ---- II
  
  Solving both I and II
  we get the speed of the train x = 19L/360 and
  the speed of the man y= L/360
  
  The train took 10 minuts to meet the man
• 13 years agoHelpfull: Yes(1) No(6)
• 190 Minutes
• 14 years agoHelpfull: Yes(0) No(1)
• Let ‘L’ be the length of train, ‘x’ be the speed of the first man,
  ‘y’ be the speed of the second man and
  ‘z’ be the speed of the train.
  
  20=
  1
  (z−x)
  and 18=
  1
  (z+y)
  
  ⇒ z=10x+9y
  
  Distance between the two men =600(z+y) mt
  Time =
  600(z+y)−600(x+y)
  (x+y)
  
  =
  600(9x+9y)
  (x+y)
  
  = 90 minutes
• 5 years agoHelpfull: Yes(0) No(0)