MBA
Exam
What is the value of the following expression?{1/(2^2-1}+{1/(4^2-1}+{1/(6^2-1}+.......+{1/(20^2-1} 1) 9/19 2) 10/19 3) 10/21 4) 11/21
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- 10/21
{1/(2^2-1}+{1/(4^2-1}+{1/(6^2-1}+.......+{1/(20^2-1} = 1/3 +1/15 +.....+1/399 = (1/1-2/3)+(2/3-3/5) +...+(10/19-11/21)
= 1-11/21
=10/21 - 11 years agoHelpfull: Yes(0) No(1)
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