(100)power 8-(111112) power 2 divide by 3 power n. find the maximum value of n.

option : a) 3
b) 2
c) 1
d)0

• since it is 100^8 converting it in the power of 2.
  so 100^8=(100000000)^2
  now,
  100000000^2-111112^2 .'. a^2-b^2=(a+b)(a-b)
  =(100000000-111112)(100000000+111112) =99888888*100111112
  
  99888888*100111112 so 9+9+8+8+8+8+8+8=66 66 is divisible by 3 but not 9 so ans should be ->3^1
• 7 years agoHelpfull: Yes(8) No(0)
• n=1 ::(100111112)(99888888)/3^n . 99888888 is divisible by 3.so whole value is also divisible by 3.
• 7 years agoHelpfull: Yes(7) No(0)
• since it is 100^8 converting it in the power of 2.
  so 100^8=(100000000)^2
  now,
  100000000^2-111112^2 .'. a^2-b^2=(a+b)(a-b)
  =(100000000-111112)(100000000+111112) =99888888*100111112=
  trying to divide it by 9 and 3 subsequently we will get the value of n as 3.
• 7 years agoHelpfull: Yes(5) No(6)
• 100^8=(100000000)^2 - 111112^2=1222232 = 98777768
  it is only divisible by 3^1 and not by 3^2 as the result is not following 9 divisiblty rule
• 7 years agoHelpfull: Yes(1) No(0)
• are bhai explain the question please ????
• 7 years agoHelpfull: Yes(0) No(3)