A dishonest grocer professes to sell pure butter at cost price, but he mixex it with adulterred fat and thereby gains 25%. Find the % of adulterated fat in the mixture assuming the adultered fat is freely available.

1) 20%
2) 25%
3) 33.33%
4) 40%
5) 35%

• Let us assume grocer got 100g of butter of cost price rs. 100
  since, grocer is adding adulterated fat in it, so he will sell (100-x)gm at the selling price rs.100 to gain 25%,
  
  So, 100 - (100-x)/(100-x) = 25/100 Using (S.P. - C.P.)/C.P. = 0.25
  We get x = 20
  So He is adding 100-20 i.e. 80g of butter is sold at rs. 100 means 20g of adulterated fat is added,
  
  So, 20/100 * 100 = 20% adulterated fat is present in the mixture.
• 10 years agoHelpfull: Yes(8) No(0)
• 1 0
  
  1*100/125=4/5
  
  4/5-0 1-4/5
  4/5 1/5
  
  
  4/5:1:5
  =4:1
  
  1/5*100=20%
  
  so solution is 20%
• 8 years agoHelpfull: Yes(2) No(0)