Que: A mixture of 125 gallons of wine and water contains 20% water. How much water must be added to the mixture in order to increase the percentage of water to 25% of the new mixture?

1) 10 gals
2) 8.5 gals
3) 8 gals
4) 6.66 gals
5) 8.33 gals

• 20% of 125 is 25.....i.e 100 wine and 25 water.....now 25+x=25%(125+x)..........
  so x=8.33 ans
• 8 years agoHelpfull: Yes(5) No(3)
• Ans is 8.33 gals
  in starting total mixture=125
  wine=100,water=25(20% of 125).
  after adding 8.33 total mixture=133.33
  now water=25+8.33=33.33.
  now check according to qtn 25% water of total mixture=33.33(25% of 133.33)
• 11 years agoHelpfull: Yes(3) No(3)
• We have a mixture of 125 gallons.
  Need to add water to change the ratio. Here the amount of mixture will be increase after adding water.
  At first we have 20% of water in 125 gallon mixture wine=100,water=25(20% of 125).
  Now add some water to increase the percentage of water to 25% of the new mixture.Here wine remain 100 gal.
  water is 25% so wine is 75%.
  i.e 75%=100gal.
  100%=133.33gal.
  This 133.33gal is the total(wine+water) amount of mixture.
  so new mixture having (133.33-100)=33.33 gal water.
  In the previous mixture we have 25 gal water now it become 33.33. So we add 33.33-25=8.33gal
  
  (e)8.33
  
• 8 years agoHelpfull: Yes(2) No(2)
• 125 gallons of wine & water mix has 20% water
  (i.e., 20% of 125 gallons=25 gallons )
  125 gallons of mix = 25 gallons water +100 gallons wine
  
  let's take x gallons of water is added,
  therefore,
  125+x gallons of mix = x+25 gallons of water + 100 gallons of wine
  so, in order to get 25% water in the mix,
  (x+25)/(125+x) = 25%
  x+25 = 0.25*(125+x)
  
  on solving it,
  you get as answer 8.33 gallons.
• 6 years agoHelpfull: Yes(2) No(0)
• e)8.33 gals
• 9 years agoHelpfull: Yes(0) No(4)
• Explanation- Mixture given = 125L 20% of which was water = 25 L
  So remaining 80% is milk is : 100 L
  Now we have to increase the water percentage to 25%. Therefore the milk percentage in new mixture is 75%:25% = 3:1.
  Let’s say we added ‘x’ liters of water in the mixture and quantity of Wine remains constant throughout.
  Hence % water to be added (Total Qty of Wine)/(Total Qty of Water+x)=(New Ratio of Wine)/(New Ratio of Water) =
  100/(25+x)=3/1
  X=8.5 Gallon
• 6 years agoHelpfull: Yes(0) No(0)
• Initially water in the mixture = 20%(125) = 25
  Let x gallons of water be added to change to water concentration to 25% or 1/4
  ⇒
  25
  +
  x
  125
  +
  x
  =
  1
  4
  
  ⇒
  x
  =
  25
  3
  = 8.33 gallons
• 4 years agoHelpfull: Yes(0) No(0)