MBA
Exam
Numerical Ability
Permutation and Combination
Que: A mixture of 125 gallons of wine and water contains 20% water. How much water must be added to the mixture in order to increase the percentage of water to 25% of the new mixture? 1) 10 gals 2) 8.5 gals 3) 8 gals 4) 6.66 gals 5) 8.33 gals
Read Solution (Total 7)
-
- 20% of 125 is 25.....i.e 100 wine and 25 water.....now 25+x=25%(125+x)..........
so x=8.33 ans - 9 years agoHelpfull: Yes(5) No(3)
- Ans is 8.33 gals
in starting total mixture=125
wine=100,water=25(20% of 125).
after adding 8.33 total mixture=133.33
now water=25+8.33=33.33.
now check according to qtn 25% water of total mixture=33.33(25% of 133.33) - 11 years agoHelpfull: Yes(3) No(3)
- We have a mixture of 125 gallons.
Need to add water to change the ratio. Here the amount of mixture will be increase after adding water.
At first we have 20% of water in 125 gallon mixture wine=100,water=25(20% of 125).
Now add some water to increase the percentage of water to 25% of the new mixture.Here wine remain 100 gal.
water is 25% so wine is 75%.
i.e 75%=100gal.
100%=133.33gal.
This 133.33gal is the total(wine+water) amount of mixture.
so new mixture having (133.33-100)=33.33 gal water.
In the previous mixture we have 25 gal water now it become 33.33. So we add 33.33-25=8.33gal
(e)8.33
- 9 years agoHelpfull: Yes(2) No(2)
- 125 gallons of wine & water mix has 20% water
(i.e., 20% of 125 gallons=25 gallons )
125 gallons of mix = 25 gallons water +100 gallons wine
let's take x gallons of water is added,
therefore,
125+x gallons of mix = x+25 gallons of water + 100 gallons of wine
so, in order to get 25% water in the mix,
(x+25)/(125+x) = 25%
x+25 = 0.25*(125+x)
on solving it,
you get as answer 8.33 gallons. - 6 years agoHelpfull: Yes(2) No(0)
- e)8.33 gals
- 10 years agoHelpfull: Yes(0) No(4)
- Explanation- Mixture given = 125L 20% of which was water = 25 L
So remaining 80% is milk is : 100 L
Now we have to increase the water percentage to 25%. Therefore the milk percentage in new mixture is 75%:25% = 3:1.
Let’s say we added ‘x’ liters of water in the mixture and quantity of Wine remains constant throughout.
Hence % water to be added (Total Qty of Wine)/(Total Qty of Water+x)=(New Ratio of Wine)/(New Ratio of Water) =
100/(25+x)=3/1
X=8.5 Gallon - 6 years agoHelpfull: Yes(0) No(0)
- Initially water in the mixture = 20%(125) = 25
Let x gallons of water be added to change to water concentration to 25% or 1/4
⇒
25
+
x
125
+
x
=
1
4
⇒
x
=
25
3
= 8.33 gallons - 5 years agoHelpfull: Yes(0) No(0)
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