A no. is chosen at random from the no. 10 to 99. By seeing the no. a man will sing if the product of the digits is 12.If he chooses 3 nos. with replacements then the probablty. that he will sing atleast once...?

1) 1-(43^3/45^3)
2) (43/45)^3
3) 1-(48X86)/90^3
4) 1

• The number of events for the condition that he will sing=4[34,43,62,26];
  the number of events in the sample = 90
  Probability that he will sing at least once =
  1-probability that he will not sing
  1-(86/90)^3
  Ans. 1-(43^3/45^3)
• 9 years agoHelpfull: Yes(0) No(0)