MBA
Exam
The perimeter of an isoscles trapezium is 16 cm and the shorter parallel side is one-third of the longer parallel side. If the sum of the lengths of the opposite sides of the trapezium are equal, what is the area (in sq. cm.) of the trapezium. 1) 4√3 2) 8√3 3) 12√3 4) 16√3 5) 10√3
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- 8 root 13
sum of opposite sides = 16/2=8
parallel sides are 2 and 6.
other opp sides are 4 and 4 cms.
height = Root 12 cms.
area = (2+6)*(root 12)/2= 4 root 12 = 8 root 3 sq cms - 11 years agoHelpfull: Yes(0) No(0)
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