MBA
Exam
If x+y+z = 21, then find the maximum possible value of (x+2)(y+2)(z+2).Ans. C 1) 500 2) 729 3) 1000 4) 250
Read Solution (Total 1)
I think it should be 729.
11 years ago
Helpfull: Yes(2) No(1)
MBA Other Question
n is a number such that 2n has 28 factors and 3n has 30 factors, 6n will have how many factors ? 1) 35 2) 32 3) 28 4) None of this
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