MBA Exam

If 12P + 3R + 4Q = 16, where P, Q and R are positive real numbers, then what is the maximum possible value of P3R3Q2?

1) 1
2) 2
3) 4
4) 8

Read Solution (Total 1)

1

when 4P=R=2Q = 16/8 =2
P=1/2
Q= 1
R=2

P^3*R^3*Q^2 = (1/8)*8*1*1=1
11 years agoHelpfull: Yes(1) No(1)

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