MBA
Exam
Let Z = {1, 11, 111, 1111, ..., 11111 up to 55 times} and T be a subset of Z such that the sum of no two elements of T is divisible by 3. The maximum possible number of elements in T is 1) 18 2) 19 3) 20 4) 37
Read Solution (Total 0)
MBA Other Question