If the roots of the equation (x + 1) (x + 9) + 8 = 0 are a and b, then the roots of the equation (x + a) (x + b) - 8 = 0 are(1) 1 and 9 (2) -4 and -6 (3) 4 and 6 (4) Cannot be determined

1) a
2) b
3) c
4) d

• 1) a
  (x+1)(x+9)+8=0
  gives :- x^2+10*x+17=0
  now a+b=-10 and a*b=17
  now (x + a) (x + b) - 8 = 0 gives x^2+(a+b)*x+a*b-8=0
  after substituting the values of a+b and ab we get
  x^2-10x+17-8=0
  now solving this equation we get,
  x=9,1
• 9 years agoHelpfull: Yes(0) No(0)