find the sum of digits in S when S= (10^33+2)/3 A)98B)100C)1034)106

1) B
2) A
3) C
4) D
5) NOT

• no. will be 100000.....32 times 0 and last digit 2
  when devided by 3
  we get 33333....32 times and last igit 4
  so sum= 32*3+4=100
  so b) is solution
• 11 years agoHelpfull: Yes(0) No(0)