Akash, Bhanu and Sam work on a project. After they complete 1/4th of the project, Sam takes a break. For 7 days only Akash and Bhanu work on the project. After that Sam relieves both of them. He completes the project in 5 days. Bhanu works 50% faster than Akash while Sam alone can finish the entire project in 20 days, How long would Bhanu take to finish the entire project?I am getting 21 Days. TIME SHP Ques. Tag me while the posts..

1) 25 Days
2) 23 1/3 days
3) 21 Days
4) 22 1/2days

• If 1 day work of Akash, Bhanu and Sam is 1/A, 1/B & 1/C respectively
  3/4 Work remains after Akash, Bhanu and Sam completes the 1/4 work
  Sam's 1 day work=1/20
  As Sam completes the remaining work in 5 days, work done by him=5*1/20=1/4
  So the work done by Akash and Bhanu for 7 days=1 -(1/4)-(1/4)=1/2
  Work of 1 day of Akash & Bhanu=1/A +1/B =1/(7*2)=1/14
  Given Bhanu work 50% faster than Akash So 1/B=(3/2)(1/A) or 1/A=(2/3)(1/B)
  Substituting in above equation (2/3)(1/B)+1/B=1/14 =>1/B=3/70
  So Bhanu can finish the entire work in 70/3 =23 1/3 days
  
• 11 years agoHelpfull: Yes(0) No(0)