5 members of a team are weighed consequently and their average weight calculated after each member is weighed.if the average weight increases by one kg each time how much heavier is the last player than the first one?

• Let five members of a team be a,b,c,d and e .
  Assume x be the avg weight of a then a=x(given) -->eqn 1
  (a+b)/2=x+1;
  (a+b+c)/3=x+2;
  (a+b+c+d)/4=x+3 --> a+b+c+d=4x+12; -->eqn2
  (a+b+c+d+e)/5=x+4; putting the value of eqn1 and eqn2 in this eqn, we get
  4a+12+e=5a+20; on solving
  e=a+8;
  Therefore the last player e is 8 kg heavier than first player a.
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