8 men can do a piece of work in 12 days.after 6 days of work 4 more men were engaged to finish the work.in how many days would the remaining work be completed?

• by using the formula of M1D1=M2D2
  8M*12=8M*6+12*x
  96=48+12x
  x=4
• 7 years agoHelpfull: Yes(4) No(0)
• Total work= 96
  For 6 days, 8 men do 8*6= 48 part of the work
  Remaining work=96-48 i.e. 48
  Now ,More 4 more men gets added to the work
  So total number of men presently to do the work= 8+4=12 men
  Therefore the remaining part of the work will be completed in 48/12= 4 days(Answer)
• 7 years agoHelpfull: Yes(0) No(0)
• 1 day 1 man capacity =1/(8*12)
  A/Q,
  1=(6*8)/(8*12) + (12*x)/(8*12)
  => x=4
• 6 years agoHelpfull: Yes(0) No(0)