a does half as much work as b in 3/4th of the time.if together they take 18 days complete a work,how much time shall b take to do it alone?

• Time taken by A = time taken by B
  A/2=3B/4
  A/B=3/2(time)
  A/B=2/3(efficiency)
  Given that A and B can do a work in 18 days so total work will be 18×5=90(5=3+2)
  Then work done by B alone= 90/3=30
• 7 years agoHelpfull: Yes(10) No(3)
• Consider a can do 30 unit of work then
  according to question
  a=30 unit
  b=(30/2)*4/3=20 unit
  Total unit of work =(30+20)*18 unit
  for b=50*18/20
  solving,we get
  b=45 days
• 6 years agoHelpfull: Yes(2) No(1)
• A/Q
  A/2=B*(3/4)
  => A/B=6/4
  => A=6/4*B ----------- eq1
  
  A+B=1/18 ------------eq2
  
  by solving 1 and 2
  we get B=45
• 6 years agoHelpfull: Yes(2) No(1)