a swimming pool has 3 drain pipes .the first two pipes a and b operating simultaneously can empty the pool in half the time than c,the 3rd pipe alone takes to empty it.pipe a working alone takes half the time taken by pipe b.together they take 6 hr 40min to empty the pool.time taken by pipe a to empty the pool is how much?

• A : B : C = 2x : x : 3x/2 => 4:2:3
  
  together they can empty in 400 mints
  in one minute 1/400
  a can empty it in 1/400 * 4/9 = 1/900
  900 mints or 15 hrs
• 7 years agoHelpfull: Yes(4) No(3)
• is the answer 20/9 hrs or 2 2/9 hrs
• 7 years agoHelpfull: Yes(2) No(1)
• a,b and c complete the work in following days.
  a->15 days
  b->30 days
  c->20 days
• 7 years agoHelpfull: Yes(0) No(1)
• Let a take x hrs to complete the work. So b will take 2x hrs to complete it.
  Together they do the work in 6 hr 40 mins or 400 mins.
  So (1/x + 1/2x) = 1/400 x=600.
  a takes 600 mins or 10 hrs to complete the work. b takes 1200 mins or 20 hrs to complete it.
  c will take twice of 6 hrs 40 mins or 800 or 13 hrs 20 mins to do it.
• 7 years agoHelpfull: Yes(0) No(7)