ABC is a right angled isosceles triangle, right angled at B with equal sides measuring 180m. A person has to travel from point A to point C. The person can travel along the sides as well as the interior of the triangle. If a person moves along AB with a speed of 5 m/s and with a speed of 3 m/s on any other path, then find the distance that he needs to cover along the path AB so as to minimize the total time taken

1) 0 M
2) 180 M
3) 45 M
4) 130 M

• To meet for the 1st time, they together will travel 10 m
  to meet for the 2nd time and so on they have to travel 20 m
  So total distance traveled to meet for d 23rd time is 10+20*22 ie 450
  Distance traveled by page(starting from A) is 450*2/7 = 120+60/7
  
  Therefore distance from A after 23rd meet is 60/7 m
• 11 years agoHelpfull: Yes(0) No(0)