Elitmus Exam Numerical Ability Area and Volume

A rectangle is inscribed in circle of area pi/2 with radius r,then what is perimeter of rectangle
1)2r
2)8r
3)2sqrt(2)r
4)4sqrt(2)r

Read Solution (Total 1)

Area = pi*r*r=pi/2 (given)
on solving we get;
r=1/root2

Now the diagonal of the rectangle will be double the radius ,since the radius of circle will act as the mid point of any diagonal.
So diagonal= 2* (1/root 2) = root 2
Now using pythagoras theorem we have;
hypotenuse = root 2
so length of sides will be 1.
so perimeter = 2 (1+1)= 4
= 2sqrt(2)r= 2*root 2 * (1/ root 2) = 4
7 years agoHelpfull: Yes(7) No(9)

Elitmus Other Question

if v,w,x,y,z are non negative intergers each leass than 7,then how many distinct combinations are possible of(v,w,x,y,z) satisfy v(7^4) +w(7^3)+ x(7^2)+ y(7) +z=151001 a triangle with sides 3,4,5 are present,then we draw the square according to that side of square is base(each side) of triangle,then what is the area which three squares are join together.