Elitmus
Exam
Numerical Ability
Number System
49 000 000 has k odd no of divisors then how many divisors have 21 000 000
Read Solution (Total 3)
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- 49000000=7^2*2^6*5^6
so no of odd divisors is 3*7=21=k
21000000=3*7*2^6*5^6
so no of odd divisors is 2*2*7=28 - 7 years agoHelpfull: Yes(6) No(1)
- 49000000=7^2*2^6*5^6
so no of divisors is 3*7*7=147=k
21000000=3*7*2^6*5^6
so no of divisors is 2*2*7*7=196 - 7 years agoHelpfull: Yes(3) No(6)
- 21000000 = 3*7*2^6*5^6
so odd no is 3, 7,5,
(1+1)(1+1)(6+1)
2*2*7=28 - 7 years agoHelpfull: Yes(2) No(1)
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