if a man reduces the selling price of a fan from rs1250 to rs 1000 his loss increses by 20%.the cp of the fan is?

• Let CP = x
  
  case 1:
  let loss % = L
  so we have
  L = ((x-1250) / x)*100
  
  case 2:
  loss % = (L+20)
  so we have
  
  L+20 = ((x-1000) / x)*100
  
  solve both equation for x we get
  x = 1250
• 7 years agoHelpfull: Yes(5) No(1)
• loss=250/20 *100
  =1250
  cp=1250+1250
  =2500
• 7 years agoHelpfull: Yes(1) No(9)
• let C.P. be x
  loss1 = x-1000
  loss2 = x-1250
  (x - 1000) = (x - 1250) + 20/100
• 7 years agoHelpfull: Yes(1) No(3)
• Rs. 2500
  
  Let CP be Rs. x
  Loss when SP is Rs. 1250 = x -1250
  Loss when SP is Rs. 1000 = x - 1000
  According to given condition, 120% of (x-1250)=(x-1000)
  => (120/100)*(x-1250) = (x-1000)
  => 6 (x-1250) = 5 (x-1000)
  => 6x - 7500 = 5x - 5000
  => x = 2500
• 6 years agoHelpfull: Yes(1) No(0)
• Let C.P. be x
  x-1000=(x-1250)*20x/100
  on solving x=937.5
• 7 years agoHelpfull: Yes(0) No(2)
• let CP = x
  
  (x-1250) = (x-1000) + (20/100)*x
  
  solve x = 11250
• 7 years agoHelpfull: Yes(0) No(2)
• Cp will be 1250
• 7 years agoHelpfull: Yes(0) No(0)
• c.p will be 1250.
  initially c.p=s.p=1250 %loss=0%
  when s.p change i.e 1000 c.p=1000
  %loss=20% we can say loss increased by 20 %
• 7 years agoHelpfull: Yes(0) No(0)
• Simple logic:
  If we observe the difference in S.P=1250-1000=250
  which caused =20% loss
  It means 20%=250
  then 100%=1250 Ans
• 2 years agoHelpfull: Yes(0) No(0)