What is the 8th term in the series 1,4, 9, 25, 35, 63, . . .

• there are two series 1^2-1,3^2-1,6^2-1,9^2-1=80
• 7 years agoHelpfull: Yes(8) No(24)
• ANS 262
  1 = 21 – 1
  4 = 22 – 0
  9 = 23 + 1
  18 = 24 + 2
  35 = 25 + 3
  68 = 26 + 4
  So 8th term is 28 + 6 = 262
• 7 years agoHelpfull: Yes(4) No(13)
• 2^2+0 = 4 which is second term
  2^3+1 = 9 third term
  2^4+2 = 18 fourth term
  2^5+3 = 35 fifth term
  2^6+4 = 68 sixth term
  2^7+5 = 133 seventh term
  2^8+6 = 262 eighth term
  so answer is 262
• 6 years agoHelpfull: Yes(4) No(1)
• The riddle follows the following sequence;
  (x*2+2, +1, +0, -1, -2)
  
  So 2nd number: 1 x 2 + 2 = 4
  
  3rd number: 4 x 2 + 1 = 9
  
  4th number: 9 x 2 + 0 = 18
  
  5th Number: 18 x 2 -1 = 35
  
  hence the answer;
  
  i.e. 6th Number = 35 x 2 – 2 = 68
• 7 years agoHelpfull: Yes(2) No(7)
• 5*7=35, 7*9=63, Next 8th term would be 9*11=99.
• 7 years agoHelpfull: Yes(2) No(3)
• 67
  1-9=8
  9-35-16
  35-67=32
• 7 years agoHelpfull: Yes(1) No(18)
• 8th term is 13*11=143
• 6 years agoHelpfull: Yes(1) No(2)