Elitmus
Exam
Numerical Ability
Arithmetic
if 47.2506=4A+7/B+2C+5/D+6E,then the value of 5A+3B+6C+D+3E is what?
Read Solution (Total 4)
-
- 4*A + 7/B + 2*C + 5/D + 6*E =47.2506
=> 4 * A + 7/B + 2 *C + 5/D + 6*E = 40 + 7 + 0.2 + 0.05 + 0.0006
Comparing the terms on both sides, we get :
4*A =40, 7/B = 7, 2*C = 0.2, 5/D = 0.05, 6*E = 0.0006
A = 10,
B = 1,
C = 0.1,
D = 100,
E = 0.0001.
5*A + 3*B + 6*C + D + 3*E =(5*10) + (3*1) + (6*0.1) +100 +(3*0.0001)
=50 + 3 + 0.6 + 100 + 0.003 = 153.6003. - 7 years agoHelpfull: Yes(17) No(1)
- why did you take d=100 please clear my doubt......
- 7 years agoHelpfull: Yes(1) No(0)
- 4×10+7/1+2/10+5/100+6/10000
A=10;B=1;C=1/10;D=100;E=1/10000
ans is 153.6003 - 7 years agoHelpfull: Yes(0) No(0)
- @ RAJAT
5/d = 5/100
d ==> 100 - 7 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question