General
Maths Puzzle
Numerical Ability
Present ages of Sameer and Anand are in the ratio of 10 : 8 respectively. Three years hence, the ratio of their ages will become 22 :18 respectively. What is Anand's present age in years?
Read Solution (Total 3)
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- ratio of present ages of SAMEER and ANAND is 10:8=5:4
let their present ages 5x and 4x respectively
3 yrs hence ratio of their ages will be 22:18=11:9
so (5x+3)/(4x+3)=11/9
or,45x+27=44x+33
or,45x-44x=33-27
or,x=6
ANAND'spresent age is 4*6=24yr - 7 years agoHelpfull: Yes(1) No(0)
- Then, 5x + 3 = 11
4x + 3 9
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years. - 7 years agoHelpfull: Yes(0) No(0)
- present ages of Sameer and Anand in ratio
Sameed : Anand
10 : 8 => 10/8 (or) 10x/8x
after 3 years their ages will be 10x+3/8x+3
after 3 years ages in ratio are
Sameed : Anand
22 : 18 => 22/18
we can write that 10x+3/8x+3 = 22/18
18(10x+3)=22(8x+3)
180x+54=176x+66
180x-176x=66-54
4x=12
x=3
so present age of Anand = 8x
=8(3)
=24 years - 7 years agoHelpfull: Yes(0) No(0)
General Other Question
1, -1, 2, -3, 4, -7, 6, -11, 8, -15, 14, ----------
2,1=9
4,2=18
5,3=18
6,3=27
then
9,4=?