A 10 hectare field is reaped by 2 men, 3 women and 4 children together in 10 days. If working capabilities of a man, a woman and a child are in the ratio 5:4:2, then a 16 hectare field will be reaped by 6 men, 4 women and 7 children in how many day??

• (workers)*days/work1= workers2*days/work2
  
  here workers are 2*5+3*4+4*2=30
  similarly second workers = 6*5+4*4+7*2=60
  and work here is 10 hectare and 16 hectare ,
  so now put the values
  30*10/10=60*x/16
  
  x=8
• 7 years agoHelpfull: Yes(15) No(2)
• using the formula
  M1*D1/W1=M2*D2/W2
  M1=5*2+4*3+2*4 = 30
  M2=5*6+4*4+2*7 = 60
  
  D1=10, W1=10
  D2= x, W2= 16
  
  now applying the formula
  30*10/10=60*x/16
  30*16=60x
  x=30*16/60
  x=8 days
• 7 years agoHelpfull: Yes(6) No(0)
• 1st, in 10 days 10 hectare field is reaped by 2 men, 3 women and 4 children together
  so , in 1 day 10/10=1 hectare field is reaped by 2 men, 3 women and 4 children together
  now working capabilities of 1 man, 1 woman and 1 child in 1 day are in the ratio 5:4:2
  then working capabilities of 2 man, 3 woman and 4 child in 1 day are in the ratio (5*2):(4*3):(2*4)
  =10:12:8
  let the total work done be 10x+12x+8x = 30x in one day
  so for 10 days it will be 30x * 10 and they graze 10 hectares
  so for one hectare it will be(30x*10)/10............(1)
  
  similarly for 6 man,4 women and 7 child
  work done will be (6*5):(4*4):(7*2)
  it will be 30:16:14
  let the total work done be 30x+16x+14x = 60x in one day
  so for y days it will be 60x * 10 and they graze 16 hectares
  so for one hectare it will be(60x*y)/16......................(2)
  
  equalizing (1) and (2)
  
  we get y=8;
  hence 8 days required
• 7 years agoHelpfull: Yes(1) No(0)
• 1st, in 10 days 10 hectare field is reaped by 2 men, 3 women and 4 children together
  so , in 1 day 10/10=1 hectare field is reaped by 2 men, 3 women and 4 children together
  now working capabilities of 1 man, 1 woman and 1 child in 1 day are in the ratio 5:4:2
  then working capabilities of 2 man, 3 woman and 4 child in 1 day are in the ratio (5*2):(4*3):(2*4)
  =10:12:8=5:6:4
  let work done by 2 man, 3 woman and 4 child in 1 day are 5x ,6x and 4x respectively
  so total work done by 2 man, 3 woman and 4 child in 1 day are (5x+6x+4x)=15x
  now 15x=1..............(as 1 hectare field)
  or, x=1/15
  again working capabilities of a man, a woman and a child are in the ratio 5:4:2
  so work done by 6 man, 4 woman and 7 child in 1 day are 5*6/15 ,4*4/15 and 2*7/15 respectively
  or , 2,16/15 and 14/15 respectively
  total 2+16/15+14/15=4 hectare field
  then a 16 hectare field will be reaped by 6 men, 4 women and 7 children in 16/4= days
• 7 years agoHelpfull: Yes(0) No(3)
• (workers)*days/work1= workers2*days/work2
  
  here workers are 2*5+3*4+4*2=30
  similarly second workers = 6*5+4*4+7*2=60
  and work here is 10 hectare and 16 hectare ,
  so now put the values
  30*10/10=60*x/16
  
  x=8
• 6 years agoHelpfull: Yes(0) No(0)
• Given 1 Man=5 units, 1 Woman=4 units, 1 Child=2 units. This is the amount of work that can be done by 1M, 1W, 1C. this is given in ratio. Now just apply the formula which is, (M+W+C)*Days*hours/ amount of work= (M+W+C)*Days*Hours/ Amount of work.
  
  Just apply the values along with the coefficients. And you will get the result.
  The answer is 8 days.
• 6 years agoHelpfull: Yes(0) No(0)