if two numbers are each divided by the same divisor,the remainders are respectively 3 and 4.if the sum of the two numbers be divided by the same divisor,the remainder is 2.the divisor is

• taking an example
  13=5(2)+3
  14=5(2)+4
  
  13+14=27
  27=5(5) +2
  
  hence divisor = 5
• 7 years agoHelpfull: Yes(7) No(0)
• Given is ,
  
  x=md+3
  and y= nd+4
  Summing up the above two equations, we get
  x+y =(m+n)d+7
  But we are given that the remainder is 2, Thus we can write the above sum as -
  x+y =(m+n+1)d + 2
  which implies the value of d=5
• 7 years agoHelpfull: Yes(6) No(0)
• For these type of question there is a direct formula
  Let m and n be two numbers and x is divisor
  M/x gives remainder r1
  N/x gives remainder r2
  (M+N)/x gives remainder r3 then
  X=r1+r2-r3
  Here
  X=3+4-2
  =5
• 6 years agoHelpfull: Yes(2) No(0)
• first take on the question is both the nos are consecutive since remainder is n and n+1 i.e 3,4.
  now remainder is 3 and 4 so divisor must be greater than 4 for sure.so next is try for 8,9 or any such no.s to make the primary statement true its always 5 as divisor
• 7 years agoHelpfull: Yes(1) No(0)
• Soln by example:
  
  18%5=3
  24%5=4
  
  Now 18+24=32
  
  so, 32%5=2
  
  Hence the no is 5
• 7 years agoHelpfull: Yes(1) No(0)
• 5. 8/5 gives reminder 3 and 9/5 gives 4 and 17/5 gives 2
• 7 years agoHelpfull: Yes(0) No(2)
• divisor=1st remainder+2nd remainder-3rd remainder=3+4-2=7-2=5
  hence divisor=5
• 6 years agoHelpfull: Yes(0) No(0)