a two dices have four faces (1, 2, 3, 4) both are simultaneously threw what is the probability of sum of the faces is prime

• 9/16
  
  Total outcomes with four faces (1,2,3,4) = 4x4 = 16
  Favorable cases are (1,1) (1,2) (1,4) (2,1) (2,3) (3,2) (3,4) (4,1) (4,3), total 9
  So required probability = 9/16
• 6 years agoHelpfull: Yes(24) No(1)
• We have four faces..1,2,3,4..
  Now the favourable cases are
  1,1 2,1 3,2 4,1
  1,2 2,3 3,4 4,3
  1,4
  Now total favourable 9 cases and
  Total are 16
  Hence the ans is 9/16
• 6 years agoHelpfull: Yes(1) No(1)
• 7/16 incorrect
  9/16 currect bkz missing (1,4)(4,1) it is the sum of the 5 which is also prime number
• 6 years agoHelpfull: Yes(1) No(0)
• 9/16
  2 dices with 4 faces so 4*4=16
  total possible of getting prime num is 9
  so probability is 9/16
• 6 years agoHelpfull: Yes(1) No(0)
• total = 4*4=16 is sample space for throwing two dices. now using that four combination sum of primes comes only (1,1) or (2,1) or (1,2 ) or (3,4) or (4,3) or (2,3) or (3,2) these are all possible combination .
  so answer is 7/16.
• 6 years agoHelpfull: Yes(0) No(4)
• 9/16 ans
  total cases= 4*4=16
  favourable output prime number sum{(1,1),(1,2), (2,1), (2,3), (3,2), (1,4), (4,1), (3,4), (4,3) } ie total=9
  so probability=9/16 ans
• 6 years agoHelpfull: Yes(0) No(0)