In an examination a candidateobtained 32% marks and failed by 16 marks. Another candidate obtained 36% marks which is 10 marks more than the minimum necessary marks to pass. Find the passing marks?

• Let us Assume the pass marks be 'X'
  Now,
  Candidate 1 obtained 32% of marks which is 16 marks less than the pass marks
  i.e 32%=X-16----------(1)
  similarly,
  Candidate 2 obtained 36% of marks which is 10 marks more than pass marks
  i.e 36%=X+10---------(2)
  Now,(2)-(1) gives
  4%=26
  =>32%=(32/4)*26=208
  Therefore ,Pass marks=208+16=224
  
  similarly if we consider 36%=(36/4)*26=234(10 marks more than the pass marks)
• 6 years agoHelpfull: Yes(3) No(0)
• Difference in percentage mark obtained = 4%
  Difference between there mark scored = 26
  4% of total mark = 26
  32% of total mark = 26 * 8 = 208
  then pass mark= 208 +16= 222
• 6 years agoHelpfull: Yes(0) No(0)
• let total amount be x
  a = 32x/100
  b =36x/100
  (36x/100)-10 =(32x/100)+16
  x =650
  a=(32(650)/100)-10)
  a =224
  similarly b =224
  pass mark is 224
• 6 years agoHelpfull: Yes(0) No(0)