Elitmus
Exam
Logical Reasoning
Cryptography
XCL
* ZCB
_________
LZXP
SZRR
CCZB
____________
ZDKBKP
___________
Read Solution (Total 8)
-
- The problem is written like:
XCL
ZCB
------------------------------
LZXP
SZRR
CCZB
-------------------
ZDKBKP
Here we can see that (Final answer's left most digit that is Z. It depends upon C. Obviously C is added to a carry 1.(The carry after adding two digits will always be 1. Adding 3 digits may give carry either 1 or 2)).
So obviously C+1=Z i.e {c,z}={{1,2},{2,3},{3,4},{4,5},{5,6}.{6,7},{7,8},{8,9}}(note: c can't be 0 so z can't be 1.)
Now hit and take trial and observe CCZB must satisfied. U'll see that c=7 and z=8. Now put all the values obtained all across and use your brain. You'll get like this:
9 7 3
X C L
8 7 4
Z C B
__________________
3 8 9 2
L Z X P
6 8 1 1
S Z R R
7 7 8 4
C C Z B
---------------------
8 5 0 4 0 2
Z D K B K P - 7 years agoHelpfull: Yes(7) No(2)
- 9 7 3 x 8 7 4
- 7 years agoHelpfull: Yes(4) No(5)
- The question uses unit- digit method. Divide the question in 3 parts-
XCL
B
--------
LZXP
--------
XCL
C
---------
SZRR
________
XCL
Z
________
CCZB
________
Take the one with most repeating variables. I will take case 2
XCL
C
_______
SZRR
_______
start with R=1, take its caes like 3*7 and 7*3 and so on.
I found 7*3 working, after trying 3*7
this way got the values, after that with minimum trials.
values-
973
847
_______
3892
6811
7784
________
850402
________
FOr practice goto - elitmuszone.com (Its a great website) - 7 years agoHelpfull: Yes(3) No(0)
- Go for the second product line, i.e. XCL*C=SZRR.
So basically you have to think about CL*C such combination which returns the same product value in unit digits (i.e. RR)
While trying, you will get combinations for CL*C like (37*3), (73*7), (47*4) etc.
so (73*7) fits proper.
Hence
answer is 973 - 6 years agoHelpfull: Yes(1) No(0)
- 973*874
First hit and trial with value of R
Take R=1 - 7 years agoHelpfull: Yes(0) No(0)
- Go for the second product line, i.e. XCL*C=SZRR.
So basically you have to think about CL*C such combination which returns the same product value in unit digits (i.e. RR)
While trying, you will get combinations for CL*C like (37*3), (73*7), (47*4) etc.
so (73*7) fits proper.
Hence
answer is 973 - 6 years agoHelpfull: Yes(0) No(0)
- C*C=R and C*L=R. If C=7 and L=3 then R=1. And Z is 1 more then C so Z is 8. 8*X should give 77, which is only possible when X=9 and Z*C gives a carry of 5. Therefore, Z is 8, C 7, X 9, B 4, D 5, L is 3, S is 6 and K is 0. Hence 973*874=850402
- 6 years agoHelpfull: Yes(0) No(0)
- 973
*874
______
3892
6811
7784
______
850402 - 2 years agoHelpfull: Yes(0) No(0)
Elitmus Other Question