Three men A ,B and C working together can do a job 6 hours less time than A did alone ,1 hour less time than B alone and half the time needed by C .In how many days will A finish the work alone

• Time taken by A =x hours.
  Therefore taken by A,B and C together = (x-6),
  Time taken by B = (x-5).
  Time taken by C=2(x-5).
  Rate of work of A + Rate of work of B + Rate of work of C = Rate of work of ABC.
  
  [(1/x)+{1/(x-5)}+ {1/(2(x-6))}]= 1/(x-6);
  
  On Solving X =3,40/6.
  
  Taking x =3 hours.
  1/[(3/20)+(3/5)] = 4/3hours.
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