A worker was arranging some particular number of cylindrical aluminium soda cans in a square box but the box became full and there were 9 cans remaining to be put in. Then, he started arranging all Cans in a rectangular box where he could arrange 6 cans more along the length than the breadth after putting all the cans in the rectangular box. He found out that there was still space left for another 6 cans. What is the number of cans the worker had if it is known that the number of cans were More than 10 and no can was put on top of another can?

• Ans.34 cans
  
  In a square the number of cans that can be arranged will be a perfect square and has to be >10.
  Start with 16, in rectangular box assume number of cans along breadth are x and thus along length are x+6. So x(x+6)=16+9+6 which gives positive x as 54, not possible.
  Next sqaure is 25. So x(x+6)=25+9+6 which gives x=4.
  So number of cans that can fit in rectangular box are 40 and thus number of cans worker had were 40-6=34.
• 6 years agoHelpfull: Yes(2) No(0)
• If 9 cans were remaining to be put into the square box after it becomes full
  that means the sq. of the number has to be greater than 9
  
  the length contains 6 more cans than breadth.
  i.e. let breadth has x cans ,so length has (x+6) cans.
  ....................................................
  if we assume 4 (as 2,3 squares give you 4,9 which are not greater than 9), it gives 16
  so for square, 16+9=25
  if we arrange 25 in rectangular box ..it would look like..
  
  **** ******
  **** ******
  **** * ---here we can see ...only 5 more cans can be arranged..so as per the question --He found
  out that there was still space left for another 6 cans. so 4 didnt worked..
  
  if we assume 5(5*5=25)
  so for square, 25+9=34
  if we arrange 25 in a rectangular box ..it would look like..
  
  **** ******
  **** ******
  **** ---here we can clearly see ....6 places are left for 6 cans..
  
  so 34 cans...
• 6 years agoHelpfull: Yes(0) No(0)
• Ans 18 cans.
  The worker initially filled 9 cans in the square box having 9 can remaining.
  Then when he took the rectangular box, he could accomodate the remaining 9 cans by the breadth side of the box. Also thus, he will still have space for 6 cans by the length.
• 5 years agoHelpfull: Yes(0) No(2)