accenture
Exam
Numerical Ability
Time and Work
If 50 programmers can write 50 lines of code in 50 minutes, then how much time would it take 5 programmers to write 5 lines of code?
Read Solution (Total 13)
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- 50 minutes
50 P ----- 50 L ----- 50 M
5 P ------ 50 L ----- 50x10 M (Less programmers more time)
5 P ------ 5 L ------ 50x10/10 = 50M (Less lines less minutes) - 7 years agoHelpfull: Yes(8) No(0)
- 50p->50l->50m
5p->5l->?
250->50
250->?
x=12500/250=50min - 7 years agoHelpfull: Yes(4) No(0)
- 50 minutes.
50 programmer takes 50 minutes to type 50 lines,
Then 1 programmer will take 50 mins to type 1 line. So 5 programmer 50 minutes - 7 years agoHelpfull: Yes(3) No(0)
- 1 line of code contain 10 minutes then 5 lines of code contain 50 minutes
- 7 years agoHelpfull: Yes(2) No(0)
- 50 Programmer can write 50 Lines of code , so 5 programmer can write 50/10 lines of code,
50 lines of code can be written in 50 minutes, so 5 lines of code can be written in 50/10 minutes,
50/10 lines of code can be written in 50/10*10 = 50 minutes - 7 years agoHelpfull: Yes(1) No(3)
- answer is 50 minutes.
50 prog. write 50 lines in 50 minutes.
-now lest say 50 prog are reduced to 5 prog.
5 prog. write 50 lines in 50*10 min.
5 prog. write 50 lines in (50*10)/10=50 minutes - 7 years agoHelpfull: Yes(1) No(0)
- 50 minutes
- 7 years agoHelpfull: Yes(0) No(2)
- 50*50 (programmers* min) / 50 ( lines) = 5(programmers)*M(minutes) / 5 (L)
=> M= %50mins - 7 years agoHelpfull: Yes(0) No(1)
- 50p can write 50L in 50m
5p can write 5L in 25 m - 7 years agoHelpfull: Yes(0) No(5)
- time remains the same and so 50 mins
- 7 years agoHelpfull: Yes(0) No(0)
- 50 minutes
- 7 years agoHelpfull: Yes(0) No(0)
- p1/p2 * m1/m2 = w1/w2
50*50 = 50
--------- -----
5* x 5
x=50 - 6 years agoHelpfull: Yes(0) No(0)
- As we have 50 programmers ------50 lines of code--------50 min
5 programmers -------5line of code------------T min
hence,there is one formula
(P1*T1)/W1=(P2*T2)/W2;
WHERE p =person
t=time
w=work
so according to the equation:(50*50)/50=(5*T)/5;
T=50 min(answer) - 5 years agoHelpfull: Yes(0) No(0)
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