Let S be the number of 6 digit numbers formed by using 1,2,3,4,5,6 without repetition and R be the number of 5 digit numbers formed by 1,2,3,4,5,6 without repetition. Find S-R.

• Answer = 0;
  ---------Explanation------
  It can be done using Factorial :-
  As we need without repetition. So same digit can't be used twice.
  S=6*5*4*3*2*1 = 6!
  R=6*5*4*3*2 = 6!
  So , S - R = 0
• 6 years agoHelpfull: Yes(21) No(0)
• There are 8 numbers divisible by 4.
  numbers ends with xyzq12
  xyzq16
  xyzq24
  xyzq32
  xyzq36
  xyzq52
  xyzq56
  xyzq64
  Still four places are there for xyzq, so 4! possible(without repetition). Totally 8 number, ultimately 4!*8=192.
  3!*8=48.
  192-48=144.
  Final answer is 144.
• 6 years agoHelpfull: Yes(4) No(1)
• What are my chances...?
  
  Verbal = 74.80
  Problem Solving = 52.14
  Quantitative = 65.22
• 6 years agoHelpfull: Yes(3) No(10)
• Sorry, I forgot to mention that "both the 5 & 6 digit numbers should be divisible by 4". I think answer will still be 0.
  Thanks Utkarsh.
• 6 years agoHelpfull: Yes(2) No(0)
• 6-digit nos. using 1,2,3,4,5,6 without repetition =6!=720
  5-digit nos. using 1,2,3,4,5,6 without repetition =6p5=720
  so, S-R=0
• 6 years agoHelpfull: Yes(2) No(0)
• 0
  s=6*5*4*3*2*1
  r=6*5*4*3*2
  hence:s-r=0
• 6 years agoHelpfull: Yes(2) No(0)
• Wali ,if question says numbers must be divisible by 4 then,
  S=4! x 8
  R=3! x 8 so, S-R=192-48=144
• 6 years agoHelpfull: Yes(2) No(6)
• 6!-5! = 5!(6-1) = 120*5=600
• 6 years agoHelpfull: Yes(0) No(6)
• 0
  S= 6!
  R=6P5
  S-R=6!-6!=0
• 5 years agoHelpfull: Yes(0) No(0)
• the answer will be 0 as the total number can be formed with the digits 1,2,3,4,5,6 is 6! and the total number formed by digits 1,2,3,4,5,6 is also 6*5*4*3*2 so S-R=0
• 5 years agoHelpfull: Yes(0) No(0)