There is three bags A, B and C. In each bag there are three types of colored balls Yellow, Green and Black.

In bag A, no. of yellow colored balls are y and no. of green colored balls are g. Number of green colored balls are 4 more than the number of yellow colored balls. When one ball is picked at random then the probability of getting black color ball is 5/13. The value of y is 18 2/11% less then g.

In bag B, number of yellow colored balls is 200/9% more than that of bag A. If two balls are picked at random from bag B then the probability of getting both green color ball is 4/37. Total number of balls in bag B is 75.

In bag C, the ratio of number of green colored balls and number of black colored balls is 7 : 5. Total number of green and black colored balls is 36. If one ball is picked at random then the probability of getting one yellow ball is 7/13.

Q1. If x number of yellow balls from bag B are taken and placed into bag A and 20% of black balls from bag A are taken and placed into in bag B. If we pick one ball from bag B then the probability that the ball is of black color is 11/26. Then find the value of x?
(a) 5
(b) 6
(c) 3
(d) 2
(e) None of these

please give detailed solution