15, 51, 216, 1100, ? , 46452

a. 6630
b. 6650
c. 6560
d. 6530

• 15*3 + (2*3) = 51
  51*4 + (3*4) = 216
  216*5 + (4*5)=1100
  1100*6 + (5*6) =6630(Ans)
  6630*7+(6*7)=46452
• 6 years agoHelpfull: Yes(14) No(0)
• 15*3 + 6 = 51
  51*4 + 12 = 216
  216*5 + 20 =1100
  1100*6 + 30 =6630
• 6 years agoHelpfull: Yes(5) No(6)
• Solution:15 x 3 + 6 = 51
  51 x 4 + 12 = 216
  216 x 5 + 20 = 1100
  1100 x 6 + 30 = 6630
  6630 x 7 + 42 = 46452
  The missing number is 6630.
• 6 years agoHelpfull: Yes(2) No(2)
• 15*3 + (2*3) = 51
  51*4 + (3*4) = 216
  216*5 + (4*5)=1100
  1100*6 + (5*6) =6630(Ans)
  6630*7+(6*7)=46452
• 5 years agoHelpfull: Yes(2) No(0)
• 15*3 + (2*3) = 51
  51*4 + (3*4) = 216
  216*5 + (4*5)=1100
  1100*6 + (5*6) =6630(Ans)
  6630*7+(6*7)=46452
• 5 years agoHelpfull: Yes(0) No(0)
• 15*3+6=51
  51*4+12=216
  216*5+20=1100
  1100*6+30=6630
  6630*7+42=46452
• 4 years agoHelpfull: Yes(0) No(0)
• 6630 Explanation: Let first no. be "k" and multiple be "l"...start value of y with 3then,[(k x y) + {l x (l-1)}]Thus, we get 15 x 3 + 3 x 2 = 5151 x 4 + 4 x 3 = 216216 x 5 + 5 x 4 = 11001100 x 6 + 6 x 5 = 66306630 x 7 + 7 x 6 = 46452 Therefore, the missing number is 6630.
• 3 years agoHelpfull: Yes(0) No(0)