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15, 51, 216, 1100, ? , 46452
a. 6630
b. 6650
c. 6560
d. 6530
Read Solution (Total 8)
-
- 15*3 + (2*3) = 51
51*4 + (3*4) = 216
216*5 + (4*5)=1100
1100*6 + (5*6) =6630(Ans)
6630*7+(6*7)=46452 - 7 years agoHelpfull: Yes(14) No(0)
- 15*3 + 6 = 51
51*4 + 12 = 216
216*5 + 20 =1100
1100*6 + 30 =6630 - 7 years agoHelpfull: Yes(5) No(6)
- Solution:15 x 3 + 6 = 51
51 x 4 + 12 = 216
216 x 5 + 20 = 1100
1100 x 6 + 30 = 6630
6630 x 7 + 42 = 46452
The missing number is 6630. - 7 years agoHelpfull: Yes(2) No(2)
- 15*3 + (2*3) = 51
51*4 + (3*4) = 216
216*5 + (4*5)=1100
1100*6 + (5*6) =6630(Ans)
6630*7+(6*7)=46452 - 6 years agoHelpfull: Yes(2) No(0)
- 15*3 + (2*3) = 51
51*4 + (3*4) = 216
216*5 + (4*5)=1100
1100*6 + (5*6) =6630(Ans)
6630*7+(6*7)=46452 - 6 years agoHelpfull: Yes(0) No(0)
- 15*3+6=51
51*4+12=216
216*5+20=1100
1100*6+30=6630
6630*7+42=46452 - 5 years agoHelpfull: Yes(0) No(0)
- 6630 Explanation: Let first no. be "k" and multiple be "l"...start value of y with 3then,[(k x y) + {l x (l-1)}]Thus, we get 15 x 3 + 3 x 2 = 5151 x 4 + 4 x 3 = 216216 x 5 + 5 x 4 = 11001100 x 6 + 6 x 5 = 66306630 x 7 + 7 x 6 = 46452 Therefore, the missing number is 6630.
- 3 years agoHelpfull: Yes(0) No(0)
- 15*3=45+(3*2)=51
51*4=204+(4*3)=216
216*5=1080+(5*4)=1100
1100*6=6600+(6*5)=6630 - 3 Months agoHelpfull: Yes(0) No(0)
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