Maths
Maths Puzzle
Numerical Ability
the product of two number is 2160 and their hcf is 12. find the number of such possible pairs
Read Solution (Total 1)
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- Assume numbers to be 12x and 12y. ( Since HCF is 12)
(12x)(12y) = 2160
xy = (2160)/(12*12) = 15
Therefore, we can it as 15= 3×15, 1× 15
Possible pairs of numbers = ( 3*12, 15*12) ,(1*12, 15*12)
= (36, 60) & (12, 180) - 7 years agoHelpfull: Yes(0) No(0)
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