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Three Science classes A, B and C take a Life Science test. The average score of students of class A is 83. The average score of students class B is 76. The average score of class C is 85. The average score of class A and 8 is 79 and average score of class B and C is 81. Then the average score. Of classes A, B and C is
Read Solution (Total 10)
-
- A/n=83
A=83n
B/m=76
B=76m
C/k=85
C=85k
(A+B)/(m+n)=79
83n+76m=79n+79m
4n=3m
n=3m/4
(B+C)/(m+k)=81
76m+85k=81m+81k
5m=4k
m=4k/5 k=5m/4
(A+B+C)/(m+n+k)=(83n+76m+85k)/(m+n+k)
=(83(3m/4)+76m+85(5m/4))/(m+3m/4+5m/4) = 978m/12m
= 81.5 - 6 years agoHelpfull: Yes(4) No(0)
- (a+b+c)/3=(83+79+85)/3=81.33
- 6 years agoHelpfull: Yes(2) No(0)
- (a+b+c)/3=(83+79+85)/3=81.33
- 6 years agoHelpfull: Yes(2) No(0)
- A/n=83
A=83n
B/m=76
B=76m
C/k=85
C=85k
(A+B)/(m+n)=79
83n+76m=79n+79m
4n=3m
n=3m/4
(B+C)/(m+k)=81
76m+85k=81m+81k
5m=4k
m=4k/5 k=5m/4
(A+B+C)/(m+n+k)=(83n+76m+85k)/(m+n+k)
=(83(3m/4)+76m+85(5m/4))/(m+3m/4+5m/4) = 978m/12m
= 81.5 - 6 years agoHelpfull: Yes(1) No(0)
- (83+75+85)/3=81.33
- 6 years agoHelpfull: Yes(1) No(0)
- A/n=83
A=83n
B/m=76
B=76m
C/k=85
C=85k
(A+B)/(m+n)=79
83n+76m=79n+79m
4n=3m
n=3m/4
(B+C)/(m+k)=81
76m+85k=81m+81k
5m=4k
m=4k/5 k=5m/4
(A+B+C)/(m+n+k)=(83n+76m+85k)/(m+n+k)
=(83(3m/4)+76m+85(5m/4))/(m+3m/4+5m/4) = 978m/12m
= 81.5 - 6 years agoHelpfull: Yes(0) No(0)
- A=83n
B/m=76
B=76m
C/k=85
C=85k
(A+B)/(m+n)=79
83n+76m=79n+79m
4n=3m
n=3m/4
(B+C)/(m+k)=81
76m+85k=81m+81k
5m=4k
m=4k/5 k=5m/4
(A+B+C)/(m+n+k)=(83n+76m+85k)/(m+n+k)
=(83(3m/4)+76m+85(5m/4))/(m+3m/4+5m/4) = 978m/12m
= 81. - 6 years agoHelpfull: Yes(0) No(0)
- (a1+a2+a3....an)/x =83
(b1+b2b3......bn)/y=76
(c1+c2+c3......cn)/z =85
((a1+a2+a3....an)+(b1+b2b3......bn))/ x+y =79
((b1+b2b3......bn)+(c1+c2+c3......cn)) / y+z =81
solving above equations
4x=3y && 4z=5y
now
(a1.....an+b1......bn+c1....cn)/(x+y+z)
i.e ( 83x+76y+85z)/x+y+z
ans.
81.5 - 6 years agoHelpfull: Yes(0) No(0)
- a,b,c be number of students in class A,B,C respectively.
given:A/a=83 ------------>(1)
B/b=76------------->(2)
C/c=85------------->(3)
A+B/a+b=79-------->(4)
B+C/b+c=81--------->(5)
To Find: average=A+B+C/a+b+c
SOLUTION:
average=83a+76b+85c/(a+b+c)-------------------->(6)
Now,
In (4) substitute values of A and B from (1) and (2)
we get, 83a+76b=79a+79b
4a=3b
b=4a/3 -------------------->(7)
In (5) substitute B and C from (2) and (3) respectively,
We get:76b+85c=81b+81c
4c=5b
c=5b/4
c=5(4a/3)/4
c=5a/3 ---------------------->(8)
substitute (7) and (8) in (6)
average=(83a+76*4a/3+85*5a/3)/(a+4a/3+5a/3)
average=978a/12a
average=81.5
so,answer is 81.5 - 5 years agoHelpfull: Yes(0) No(0)
- 8 dsDsdsad
dsadsdddssd - 5 years agoHelpfull: Yes(0) No(0)
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