TCS
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Numerical Ability
Boats and Streams
The speed of a boat in still water is 10 km/hr. The stream has a current of 2km/hr. The boat takes 2 hours more to cover a trip from A to B than it took to go from B to A. What is the distance between A and B?
30 km
16 km
48 km
40 km
32 km
Read Solution (Total 5)
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- Speed of boat=10,speed of stream=2,time=2 hr
Let distance be x
(x/(10-2))-(x/(10+2))=2
x/8-x/12=2
x=48 - 7 years agoHelpfull: Yes(5) No(0)
- ans is 48
given that
x=10,y=2
for downstream x+y=d/t 10+2=d/t------1
for upstream x-y=d/t+2 10-2=d/t+2-------2
solving 1 &2 we get
time=4
and distance= 48 - 7 years agoHelpfull: Yes(1) No(0)
- (10+2)*x=(10-2)*(x+2)
x=4
hence AB=4*12
=48 - 7 years agoHelpfull: Yes(1) No(0)
- Shortcut method to find a solution
Let Distance be D, boat speed be x , stream speed be y ,Time be t
(2 × D × y)÷[(x+y)×(x-y)] = t
2D ×2/(12×8) =2
Solving D=48 - 5 years agoHelpfull: Yes(1) No(0)
- Let u be the speed of the boat in still water : u = 10 km/hr
Let v be the speed of the current : v = 2 km/hr
Let time from B to A = t hrs
Therefore, time from A to B = (t + 2) hrs
Since the time from A to B is more than the time from B to A, we get the idea that A to B is upstream (and B to A is downstream).
Speed of the boat upstream = 10 + 2 = 12 km/hr
Speed of the boat downstream = 10 - 2 = 8 km/hr
Distance from A to B (upstream) = Distance from B to A (downstream)
Therefore, with the help of Distance = Speed x Time;
8 x (t + 2) = 12 x t
8t + 16 = 12t
16 = 12t - 8t
16 = 4t
Therefore, t = 4hrs ............ (i)
Now,putting (i) into either of the distance expressions (either upstream or downstream), we will get the answer.
(I have taken the downstream expression)-
Distance (A to B or B to A) = 12 x t = 12 x 4 = 48 kms ............ (Answer) - 5 years agoHelpfull: Yes(0) No(0)
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