Bharti is a history teacher.in addition to above rule of the school she teaches exactly
one pair of
successive classes in adjacent classrooms.how many distinct trips to classes rooms are
possible for Bharti
if there are 12 classroom in school.

• If 1st and 2nd classes are adjacent:-
  Possibilities for, first class-12 2nd class-2 3rd class=8
  total=12*2*8=192
  If 2nd and 3rd class are adjacent:-
  Possibilities for, first class=12
  2nd class=2 3rd class=1
  2nd class=7 3rd class=2
  total=12*2*1+12*7*2=192
  If 3rd and last classes are adjacent :-
  Possibilities for, first class=12 2nd class=8 3rd class=2
  total=12*8*2=192
  Therefore, the total combination = 192*3=576.
• 6 years agoHelpfull: Yes(3) No(5)
• New public school have a circular layout. The school has teachers specializing in various subjects. All classroom of the school are equally spaced apart and located along its perimeter. Each Teacher needs four classes in day. There is strange rule. The first and last class has to be in the same class room. The other two classes have to be at two other distinct class rooms.
  
  now,
  Possibilities for 1st and final position=12
  if 1st and 2nd classes are adjacent then possibilities for 1st class=12
  2nd class=2
  3rd class=8
  12*2*8=192
  if 2nd and 3rd classes are adjacent then possibilities for 1st class=12
  2nd class=2 then 3rd class=1 when they are next to next for 1st class
  2nd class=7 then 3rd class=2
  Total =12*2*1+12*7*2=192
  if 3rd and last classes are adjacent then for 1st class=12
  2nd class=8
  3rd class=2
  Total =12*8*2=192
  total combinations possible=192+192=192=576
• 6 years agoHelpfull: Yes(0) No(0)