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Numerical Ability
Permutation and Combination
6 members have to be selected from different field.10 from java,5 from microsoft,8 from oracle,2 from IBM .What is the possible combination?
Read Solution (Total 12)
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- 10C1*5C1*8C1*2C1*21C2=168000
IN EVERY FIELD ONE MEMBER IS SELECTED AND IN REMAINING 21 WE SELECT 2 MEMN=BER. - 7 years agoHelpfull: Yes(40) No(7)
- Hi I have my exam on 12th,can you give me some hint or questions that were asked
- 7 years agoHelpfull: Yes(17) No(3)
- 25C2
total no. of members =25
members to be selected =6
hence, 25C6 - 7 years agoHelpfull: Yes(7) No(15)
- 25c6.as there are totally 25 members and 6 should be selected out of them.
- 7 years agoHelpfull: Yes(3) No(1)
- Members to be selected is 6
10+5+8+2=25
Answer:25C6 - 7 years agoHelpfull: Yes(2) No(5)
- 10C1*5C1*8C1*2C1*21C2=168000 IN EVERY FIELD ONE MEMBER IS SELECTED AND IN REMAINING 21 WE SELECT 2 MEMBER.
- 6 years agoHelpfull: Yes(1) No(1)
- 24 is the correct answer
- 5 years agoHelpfull: Yes(1) No(0)
- Tapan how ws ur exam can u please tell me some imp topics ?
- 7 years agoHelpfull: Yes(0) No(1)
- adding up all the fields we get a total of 25.
since selection is being asked then it is combination
6 people out of 25 means ......25C6 - 7 years agoHelpfull: Yes(0) No(7)
- 25c6
total no = 25
selection = 6 - 7 years agoHelpfull: Yes(0) No(2)
- total number of selected students are 25=10+5+8+2
selected from each field 6 membebrs=6
so 25c6 - 6 years agoHelpfull: Yes(0) No(1)
- 6c5*4c3=24
- 6 years agoHelpfull: Yes(0) No(1)
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