If a b c and d are four distinct non zero digits such that abc + cba=bdb, how many distinct values of b are possible and what are they?

• Answer: abc+cba=bdb, contain posibility of A,B,C,D=> 0,1,2,3,4==>
  it start with 000+000=000, 001+100=101,002+200=202...............500+005=505........more value except after 555+555=1110.
  
  But 600+006=606, 707+007=707 also valid.
  
  precisely cheers!!!!!!
• 6 years agoHelpfull: Yes(0) No(1)