what is next series 8,20,22,20,28,20,?

• Question posted by you is wrong. The correct question is 18,20,22,20,28,20,?
  Solution: 20 is constant. so we have 18,22,28,?
  The difference is 4 between 18,22 and 6 22,28.
  so the next will be 28+8=36
  ANS:36
• 7 years agoHelpfull: Yes(31) No(11)
• 20 cnstnt.
  remaining prts r 8,22,28,?
  logic-8*2 +6=22
  8*3+ 4=28
  8*4+ 2=34
• 6 years agoHelpfull: Yes(17) No(0)
• The logic is taking the alternate no. to form a series then we will get two series
  1st is : 8,22,28,...
  2nd is : 20,20.. which is constant
  for first series the logic is 8,8*2+4,8*3+4,....and so on.
• 7 years agoHelpfull: Yes(16) No(16)
• 8 20 22 20 28 20 ?
  20 will be even places.
  now 8 22 28 ?
  8*3-2=22
  8*4-4=28
  8*5-8=32
  
  ans will be 32.
• 6 years agoHelpfull: Yes(7) No(7)
• 22-8 = 14
  
  28-22=6
  
  14-6=8
  
  26-28= -2
  
  6-(-2)=8
  
  every time the difference is reduced by 8 so answer would be 26.
• 7 years agoHelpfull: Yes(3) No(6)
• Only consider odd places of series
  8,22,28,....
  Now ans it can be this 8,22,28,12
• 6 years agoHelpfull: Yes(1) No(0)
• Make pairs of 2 and observe that 20 is repeating alternately.
  (8,20) now add 2 in 20 (22,20) now add 8 in 20 (28,20) now add multiply of 2 and 8 i.e 16 (36,20)
  Ans is 36
• 6 years agoHelpfull: Yes(1) No(0)
• answer 22:
  8 , 20 , 22 , 20 , 28 ,20,
  
  difference: (20-8)==>12
  > (12-2)==>10
  (22-20)==>2
  >(2-2)==>0
  (20-22)==>-2
  >(8+2)==>10
  (28-20)==>8
  >(8-8)==>0
  (20-28)==>-8
  >(2+8)==>10
  (22-20)==>2
  therefore 22 hope you found the pattern
• 6 years agoHelpfull: Yes(1) No(1)
• 8,20,22,20,28,20
  8,22,28
  here the difference increased as 4,6 and 8.
  hence answer is 28+8=36
• 5 years agoHelpfull: Yes(1) No(3)
• Number other than 20 is
  8,22,28
  i.e. 8*2+6=22
  8*3+4=28
  8*4+2=34
  So,34 should be the ans
• 5 years agoHelpfull: Yes(1) No(0)
• 28+4=32
  hguy
• 7 years agoHelpfull: Yes(0) No(1)
• 8,20,22,20,28,20,42
  20 is common ,remaining series is
  8 ,22,28,42
  / / /
  14,6,14
  / /
  8, 8
• 6 years agoHelpfull: Yes(0) No(1)