A BRICK WALL CONTAINS 52 BRICKS IN ITS BOTTOM ROW AND 49 BRICKS IN THE NEXT ROW UP FROM THE BOTTOM ROW. EACH SUBSEQUENT ROW CONSISTS 3 FEWER BRICKS THAN THE ROW IMMEDIATELY BELOW IT. IF THE WALL CONTAINS 16 ROWS, HOW MANY BRICKS TOTAL MAKE UP THE WALL?

• 472 bricks
  
  Here an A.P. can be formed with first term a=52, difference d=-3, number of terms n=16
  So sum of an A.P., Sn=(n/2)[2a + (n-1)d]
  = (16/2)[2*52 + 15*(-3)]
  = 8(104 - 45)
  = 472
• 7 years agoHelpfull: Yes(3) No(0)