In a certain year between 1973 and 1978 , a child was born on friday. October 01. What was his age on wednesday, October 01,1980

• answer = age 3(born on 1976 oct 01,friday)
  clew friday and wednesday is given;
  >>fist find leap year,every 4 years have 1 leap year; every leap year is divisible by 4
  1973,74,75,76,78,79,80;
  1980 is leap year so 1976 is also leap year;
  >>every year the same date repeat next year with 1 day difference expect leap year(2 day difference);
  so 1980 oct 1 -wednesday, 1979 oct 1-monday(1980 is leap year 2 day deference because october is after feb 29 ),1978 oct 1-sunday,1976 oct 1 - friday(again leap year).
• 6 years agoHelpfull: Yes(1) No(0)
• 1976=0 year (fri)
  1977=1 year (sat)
  1978=2 year (sun)
  1979=3 year (mon)
  1980=4 year (wed) (leap year add extra one day)
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